Big File Upload
This script is a more complete version of the last one. It buffers file IO avoiding to memory starve the server if the file is a bit bigger. There is no drawback in buffering file IO, so always do it.
import os def form(): return """\ <html><body> <form enctype="multipart/form-data" action="./upload" method="post"> <p>File: <input type="file" name="file"></p> <p><input type="submit" value="Upload"></p> </form> </body></html> """ # Generator to buffer file chunks def fbuffer(f, chunk_size=10000): while True: chunk = f.read(chunk_size) if not chunk: break yield chunk def upload(req): try: # Windows needs stdio set for binary mode. import msvcrt msvcrt.setmode (0, os.O_BINARY) # stdin = 0 msvcrt.setmode (1, os.O_BINARY) # stdout = 1 except ImportError: pass # A nested FieldStorage instance holds the file fileitem = req.form['file'] # Test if the file was uploaded if fileitem.filename: # strip leading path from file name to avoid directory traversal attacks fname = os.path.basename(fileitem.filename) # build absolute path to files directory dir_path = os.path.join(os.path.dirname(req.filename), 'files') f = open(os.path.join(dir_path, fname), 'wb', 10000) # Read the file in chunks for chunk in fbuffer(fileitem.file): f.write(chunk) f.close() message = 'The file "%s" was uploaded successfully' % fname else: message = 'No file was uploaded' return """\ <html><body> <p>%s</p> <p><a href="./form">Upload another file</a></p> </body></html> """ % message
